Answer: Sonata Software GET OA 2025 | Inventory Stock Partitioning & Shipping Window Opt

Solution - E-Commerce Inventory Stock Partitioning Strategy A brute-force solution recalculates left and right sums for every index, resulting in O(N²) complexity. Instead, compute the total array sum once and maintain a running left sum. Approach Calculate the total array sum. Initialize leftSum = 0. For every index, compute: rightSum = totalSum - leftSum - currentValue If leftSum equals rightSum, return the current index. Otherwise, add the current element to leftSum. Code public class InventoryStockPartitioning { public int locatePivotIndex(int[] stockAdjustments) ...