Answer: Netflix Associate Developer Interview Question 2023 May | Trees | on-campus

Solution: Morris-Inspired In-Place Flattening (Iterative) Approach Process node by node starting from the root. At each node with a left child: find the rightmost node of the left subtree (this is where the current node's right subtree will be attached). Wire the right subtree to the rightmost node's right pointer, then move the entire left subtree to the right and set left to null. Advance to the right child and repeat. This is done in-place without extra space — each ...