Answer: Notion SWE Interview Question 2025 March | Greedy and Heaps | on-campus

Solution: Mathematical Formula Using Max Frequency Approach The minimum time is determined by the most frequent task. Imagine arranging tasks in frames of size (n+1). The most frequent task (frequency = maxFreq) creates maxFreq - 1 full frames, each needing n+1 slots. The last partial frame contains all tasks that share the maximum frequency (countOfMaxFreq). Formula: result = (maxFreq - 1) * (n + 1) + countOfMaxFreq. However, if tasks are dense enough to fill all frames with no idle ...